Geometry Determining an Angle

Introduction:

In mathematics, an angle is the branch of geometry which is defined as the two rays sharing a common endpoint to form the figure is the vertex of the angle. The amount of rotation is the magnitude of the angle that separates the two rays. For the geometric configuration and its angular magnitude the term "angle" is used. The word angle means "a corner" which is come from Latin. There are different types of angle in geometry.They are Right angle, Straight angles, acute angles, Obtuse angles, Complementary angle, Supplementary angles.


Conditions for determining an angle:


Let as assume the x be the variable for angle. Then,

Right angle

Right angle is the angle in which the value of angle is 90 degree.

If x = 90 degree, it is right angle.

Straight angle

Straight angle has the angle value as 0 degree.

If x = 0 degree, it is straight angle.

Acute angle

When the angle value is below 90 degree then it is acute angle.

If 0 < x < 90 degree, it is acute angle.

Obtuse angle

When the angle value is above 90 degree then it is obtuse angle

If x > 90 degree, it is obtuse angle.

Let as assume x and y are two angles. Then,

Complementary angle

The angles are called as complementary angle when the sum of the two angles is 90 degrees.

If x + y = 90 degree, it is Complementary angle.

Supplementary angle

The angles are called as Supplementary angle when the sum of the two angles is 180 degrees.

If x + y = 180 degree, it is Supplementary angle.

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Examples:


Example 1: find the type of angle for below values?

1. x = 10
2. x = 90
3. x = 300
Solution:

1.  The given value is x = 10 degree.

It satisfy the condition 0 < x < 90.

Therefore, it is an acute angle

2. The given value is x = 90 degree.

It satisfy the condition x = 90.

Therefore, it is right angle.

3. The given value is x = 300 degree.

It satisfy the condition x > 90.

Therefore, it is an obtuse angle

Example 2: Check whether the angles are Complementary angle or Supplementary angles for given data below?

1. x = 30, y = 60

2. x = 80, y = 100

Solution:

1. x = 30, y = 60

x + y = 30 + 60

= 90

Therefore, it is Complementary angle.

2. x = 80, y = 100

x + y = 80 + 100

= 180

Therefore, it is Supplementary angle.

Area of a Kite Geometry

Introduction about kite in geometry:

In geometry a kite, or deltoids, is a quadrilateral with two disjoint pairs of congruent adjacent sides, in contrast to a parallelogram, where the sides of equal length are opposite. The two diagonals of a kite are perpendicular and half the product of their lengths is the area of a kite. It has four vertices's. We can calculate the area for many shapes in geometry. In this article we shall discus about how to how to calculate area of kite with geometry example problems.

Source-Wikipedia

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Geometry Formula and example problems:

The space occupied by the kite is called area of kite.

Formula:

Area of kite (A) = half the product of two diagonals.

Let assume,

d1 and d2 are the two diagonal of kite.

Area of kite (A) = (d1 x d2) /2 square unit.

Example problems:

1. Find the area of kite whose diagonal length diagonal (d1) = 20cm and diagonal (d2) = 15cm.

Solution:

Given:

Diagonal (d1) = 20cm

Diagonal (d2) = 15cm

Formula:

Area of kite (A) = (d1 x d2) / 2

= (20 x 15) / 2

= 100/2

=50

Area of kite (A) = 50 cm^2

2. Find the area of kite whose diagonal length diagonal (d1) = 12cm and diagonal (d2) = 8cm.

Solution:

Given:

Diagonal (d1) = 12cm

Diagonal (d2) = 8cm

Formula:

Area of kite (A) = (d1 x d2) / 2

= (12 x 8) / 2

= 96/2

=48

Area of kite (A) = 48 cm^2

3. Find the area of kite whose diagonal length diagonal (d1) = 25cm and diagonal (d2) = 15cm.

Solution:

Given:

Diagonal (d1) = 25cm

Diagonal (d2) = 15cm

Formula:

Area of kite (A) = (d1 x d2) / 2

= (25 x 15) / 2

= 375/2

=187.5

Area of kite (A) = 187.5 cm^2

4. Find the area of kite whose diagonal length diagonal (d1) = 8cm and diagonal (d2) = 6cm.

Solution:

Given:

Diagonal (d1) = 8cm

Diagonal (d2) = 6cm

Formula:

Area of kite (A) = (d1 x d2) / 2

= (8 x 6) / 2

= 48/2

=24

Area of kite (A) = 24 cm^2

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Area of kite geometry – practice problem:


1.      Find the area of kite whose diagonal length diagonal (d1) = 12cm and diagonal (d2) = 6cm.

Answer: Area (A) = 36cm^2

2.      Find the area of kite whose diagonal length diagonal (d1) = 18cm and diagonal (d2) = 9 cm.

Answer: Area (A) = 81 cm^2

3.      Find the area of kite whose diagonal length diagonal (d1) = 8cm and diagonal (d2) = 6cm.

Answer: Area (A) = 24 cm^2

What is a Pentagon in Geometry

Introduction to Pentagon in geometry:

Pentagon is the one of the important mathematical figure in geometry.  It is a five sided polygon.  Pentagon is making with the help of 5 sides and 5 angles. Pentagon is classified into following two types.  They are

Regular Pentagon
Irregular pentagon
In this article we have to study about what is pentagon in geometry.


Brief Study about what is a pentagon in geometry?


What is Regular pentagon in geometry?

A pentagon is usually 5 sided figures.  The sides and angles are equal of the pentagon are equal in measure so it is named as regular pentagon.

What is Irregular pentagon in geometry?

Irregular pentagon is also one of the types of pentagon.  Here the sides and angles are not equal in measure.  They are different sides and angles.  So it is named as irregular pentagon.

What is the Pictorial representation of the Regular Pentagon?

What are the Properties of the regular pentagon?

5 sides are equal in measure
5 angles are equal in measure.
Sum of the interior angles measures 540 degree
Each interior angle measures 108 degree
Sum of the exterior angles measures 360 degree
Exterior angle measures 72 degree
Pentagon is formed with the help of three triangles
Pentagon has five lines of reflectional symmetry
Pentagon has five lines of rotational symmetry

What is the area of the regular and irregular pentagon?

The following formula is used to find the area of the regular pentagon,

A=`(1)/(2)` x Apothem X Perimeter

Here A is the area of the pentagon

Apothegm is the radius of the in circle of the pentagon

Perimeter is the sum of all sides of the pentagon

This is the formula to calculate the area of the pentagon.

Geometry Proportions

Introduction of geometry proportions:-

In mathematics, Proportions in arithmetic and geometry, a particular relation between groups of numbers or quantities. In arithmetic, proportions are the equality of ratios; ratio is the division of one number by another. A continued proportions is a property of every three terms in a geometric progression. A proportions is a statement that two ratios are equal such as a:b = c:d.



Example problem for geometry proportions:-


Problem1:

Are the ratios 30g: 40g and 48 kg: 72 kg in geometry proportions?

Solution:

30 g: 40 g =30 / 40 = 3 / 4

= 3: 4

48 kg: 72 kg = 48 / 72 = 4 / 6

= 4: 6           So, 30: 40 = 48: 72.

Therefore, the ratios 30 g: 40 g and 48 kg: 72 kg are in geometry proportions,

i.e. 30 : 40 :: 48 : 72.

The middle terms in this are 40, 48 and the extreme terms are 30, 72.


Problem 2:

Do the ratios 30 cm to 4 m and 20 sec to 5 minutes form a geometry proportions?

Solution:

Ratio of 30 cm to 4 m = 30: 4 × 100 (1 m = 100 cm)

= 3: 40

Ratio of 20 sec to 5 min = 20: 5 × 60 (1 min = 60 sec)

= 20: 300

= 1:15

Since, 3: 40 ≠ 1: 15, therefore, the given ratios do not form a geometry proportions.



Problem 3:

Sam works as a dental hygienist. Last week Sam ade 500 for 20 hours of work How many hours must Sam work in order to make 800?

Solution:

Sam works as a dental hygienist

50020hours=800 / x hours

20 hours * $800 = x hours * $500

16000 = $500 x

16000 / 500 = x

32 = x

Sam 32 hours work in order to make $800

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Practice problems for Geometry proportions problems:        


Problem 1:

Gabriella bought five cantaloupes for 3 How many can taloupes can Shayna buy if she has21?

Answer: 35 gabriella

Problem 2:

If you can buy one can of pineapple chunks for 5 then how many can you buy with 10 ?

Answer: 50 pineapple chunks

Problem 3:

If you can buy four bulbs of elephant garlic for 12 then how many can you buy with 96?

Answer:  8 bulbs

Problem 4:

One package of blueberries costs 6 How many packages of blueberries can you buy for 42?

Answer: 7 blueberries

Geometry Sample Test

Introduction to Geometry sample test:

Geometry is the method  of finding  the volume or  dimension of an object. Buildings, cars are some examples of geometry. Geometry sample test help students in finding the area, perimeter, circumference of  Two-dimensional figures like triangle, circle, rectangle, rhombus, trapezoid, quadrilateral etc.Geometry  sample test problems are used in real life situations such as how much water can we store in a tank. Here lot of geometry sample test questions are given with answers for our practice.


Geometry sample test:


Example 1:

Find the perimeter of square whose sides are 17 cm.

Solution:

given the side if square is 17 cm

Perimeter of the square, P = 4a

= 4 × 17 cm

=  68 cm

Hence the perimeter of square is 68 cm.

Example 2:

Find the volume of right cylinder that has radius 5 cm and height 12 cm.

Solution:

Given, r = 5 cm

h= 12 cm

Volume of circular cylinder = pi * r2 * h cu. Units

= `(22/7)` * 5 * 5 * 12 = 942

Volume of circular cylinder = 942 cm^2

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Geometry sample test:


Example 3:

The perimeter of the floor of a square room is 35m. Find the area of the floor of given perimeter.

Solution :

To find the area of a given square of perimeter 35 m, we need to measure its side. Here perimeter of the square is given, we
need to find the side of square from its perimeter.

Perimeter of square ground, p = 4a

4a = p

a = p/4

Hence, a = 35 / 4 m [since p = 22 m ]

∴ a = 8.75 m

Area of the square ground A = a2

= 8.75 m × 8.75 m

i.e. Area = 76.5625 sq.m.

Example 4:

Find the volume of the right prism whose area of the base is 450 cm^2 and height is 28cm

Solution:

Given that area of the base, A = 540 cm^2 and height (h) of the prism = 13 cm

Volume of the right prism = area of the base * height cu.units

= A * h

= 540⋅13

Volume of right prism = 7020 cm3

Geometry Parallelograms

Introduction for geometry parallelograms:

In geometry, parallelogram is a shape that has four sides where the opposite sides are parallel to each other. The main concepts of the parallelograms are,

The opposite angles are equal

The opposite sides are equal in its length and are parallel to each other.

Now we are going to see about the geometry - parallelograms and its problems.


Problems for geometry parallelograms:

Example 1:

Find the sides of the parallelogram having 10 cm which is the smaller side of the parallelogram. The longest side is 3 times the smallest side of the parallelogram.

Solution:

The smallest side of a non regular parallelogram = 10 cm (known)

The longest side of the parallelogram will be 10 × 3 = 30 cm.

This is due the opposite sides are equal in the parallelograms

Thus the other two sides are 10 cm and 30 cm respectively.

The irregular quadrilaterals sides, parallelograms = 10 + 30 + 10 + 30 = 80 cm.

Example 2:

Determine the sides of the parallelogram having 15 cm which is the smaller side of the parallelogram. The longest side is 5 times the smallest side of the parallelogram.

Solution:

The smallest side of a non regular parallelogram = 15 cm (known)

The longest side of the parallelogram will be 15 × 5 = 75 cm.

This is due the opposite sides are equal in the parallelograms

Thus the other two sides are 15 cm and 75 cm respectively.

The irregular quadrilaterals sides, parallelograms = 15 + 75 + 15 + 75 = 180 cm.

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More problems for geometry parallelograms:


Example:

Determine the area of parallelogram where the base and height of the parallelogram are 12 cm and 20.

Solution:

Given data is the base, b =12 cm and the height, h =20 cm

We know the formula for the area of parallelogram and given as,

Area of the parallelogram = b × h

Substitute the value of b and h,

Area of parallelogram = 12 × 20

= 240 cm^2

Therefore the area of a parallelogram is 240 cm^2

Geometry Concurrent Lines

Introduction to Geometry concurrent lines

Concurrence
Definition Of concurrent lines
Examples of concurrent lines
Concurrence in Triangle
Concurrence in Circle
Concurrence

The phenomenon when  multiple lines meet at a point is known as concurrence.


When two or more  lines in a plane intersect at a common point then they are said to be concurrent lines.

Examples of geometry concurrent lines

Altitudes of a triangle are concurrent lines
Angular bisector of a triangle are concurrent lines
Perpendicular bisectors of a triangle are concurrent lines
The medians of a triangle are concurrent lines
The diameters of a circle are concurrent lines

Geometry concurrent lines in a triangle


Incenter is the point of concurrence of the angular bisector of a triangle , therefore  the angular bisectors of a triangle are concurrent lines. Angular bisectors are the lines which divide each angle of a triangle in two equal angles they meet at in center.
Circumcenter is  the point of concurrence of perpendicular bisectors of a triangle, therefore perpendicular bisectors of a triangle are concurrent lines. Perpendicular bisectors of a triangle are the lines which divide each side in two equal parts they meet at the circumcenter .


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Orthocenter  is the point of concurrence of altitudes of a triangle, therefore  altitudes of a triangle are concurrent lines. Altitudes are the perpendicular from each vertex of a triangle to the opposite sides, they meet at the ortho center.
Centroid is the point of concurrence of medians of a triangle , therefore medians of a triangle are concurrent lines. Medians are the lines joining the vertex to the mid point of opposite sides, they meet at centroid.
Geometry concurrent lines in a circle.

Center of a circle is the point of concurrence of all the diameter, therefore all the diameters of a circle are concurrent lines . Diameter of a circle is the line joining  two points on the circumference passing through the center .