Monday, April 1, 2013

Solving Geometry Homework

Geometry:

Geometry is the main branches of mathematics. The geometry different types of size, shape, relative position of figures, and the properties of space. Geometry is one of the oldest sciences. The word ‘Geometry’ means learn of properties of figures and shapes and the relationship between them. A system of geometry is called Euclidean geometry. A solid geometry classified to a set of problems or objects.

(Source-Wikipedia)


Solving homework 1:


To calculate the area of a cylinder given that its radius is 8 and its length or height is 6.

Solution:

The surface area of this cylinder is 2 `pi` RL+2 `pi` R2.

= 2*3.14*8*6+2*3.14*82=703.717

The surface are of a cylinder is 703.717

Solving homework 2:

To calculate the perimeter of a rectangle given that its width is 7 and its height is 6.

Solution:

The perimeter is the distance around the rectangle, or h+w+h+w or 2h+2w.

Perimeter = 2 * 6 + 2 * 7 = 26

The perimeter of rectangle is 26


Solving homework 3:


To calculate the area of a rectangle given that its width is 8 and its height is 7.

Solution:

The area enclosed by rectangle, is h × w

Area = 7 * 8 = 56

The area of a rectangle is 56

Solving homework 4:

To calculate the area of a right triangle given that its base is 10 and its height is 8.

Solution:

The area of a right triangle is 1/2bh

Area = ½ * 10 * 8 = 40

The area of a rectangle is 56

Solving homework 5:

To calculate the side of a square given that its area is 8.

Solution:

The area is the amount of space enclosed by the square is S × S or Area=S2.

Solve this equation for S to get that or S=Area1/2 Side = area ½=81/2=2.82843

The side of this square has a length of 2.82843

Solving homework 6:

To calculate the area of  rhombus whose diagonal lengths are  8 and 12.

Solution:

The area of the rhombus= 1/2  x length of the diagonal 1 x length of the diagonal 2 .

=1/2 x 8 x 12

The area of the rhombus = 48

Sunday, March 31, 2013

Solving Geometry Perimeters

solving geometry perimeters:

Geometry is the study of all kinds of shapes and their properties.

Plane geometry  is the study of two dimensional shapes such as lines, circles, triangles etc.

Solid geometry is the study of three dimensional shapes like polygons, prisms, pyramids, sphere, cylinder, cone etc.

Perimeter is defined as the total distance around the outside of a 2D shape. Perimeter can be calculated by adding all the lengths along the periphery of a shape.

Let us see solving geometry perimeters in this article


Solving Geometry Perimeter


The Perimeter of rectangle P is the Addition of two times length l and two times width w.

Formula:           P = 2 * length + 2 * width

Example:

Find the Perimeter of rectangle for the length is 6 cm and Width is 5 cm.

Solution:

Perimeter of the rectangle          P =  2 * 6  + 2 * 5

P = 12 + 10

P = 22 cm. Answer.

Perimeter of square:

The Perimeter of any square P is the product of 4 and a side.

Formula:                P = 4 * side

Example:

Find the Perimeter of square for the side is 4 cm.

Solution:

Perimeter of the square A = 4 * 4

A = 16 cm. Answer.

Having problem with Surface Area of a Prism keep reading my upcoming posts, i will try to help you.

Solving Geometry Perimeter for parallelogram and triangle


Perimeter of Parallelogram:

The Perimeter of any Parallelogram is the addition of 2 times side a and 2 times side b.

Formula:           P = 2 * side a + 2 * side b

Example:

Find the Perimeter of Parallelogram for the side a is 7 and side b is 9 and height is 5.

Solution:

Perimeter of Parallelogram        P = 2 * 7 + 2 * 9

P = 14 + 18

P = 32 . Answer.

Perimeter of Triangle:

The Perimeter of Triangle P is the Addition of all the three sides.

Formula:           P = AB + BC + AC for triangle ABC

Example:

Find the Perimeter of triangle for the AB = 7 cm , BC = 5 cm and AC = 7 cm.

Solution:

Perimeter of the triangle            P =  7 + 5 + 7

P = 19 cm. Answer.

Tuesday, March 26, 2013

Solving Geometry Problems Online

Introduction to solving geometry problems online:

Geometry is a part of math which involves the study of shapes, lines, angles, dimensions, etc. it plays vital role real time application like elevation, projection. Learning geometry provides many foundational skills and helps to build the thinking skills of logic, deductive reasoning, and analytical reasoning. Flat shapes like lines, circles and triangles are called the Plane Geometry. Solid (3-dimensional) shapes like spheres and cubes are called Solid geometry. In this article we shall discuss about solving geometry problems online.

I like to share this Surface Area of a Hemisphere Formula with you all through my article.

Sample problems for online geometry solving:


Example 1:

The perimeter of a rectangle is 800 meters and its length L is 3 times its width W. Find W and L, and the area of the rectangle.

Solution:

Perimeter of rectangle=2L+2W,

2 L + 2 W = 800

We now rewrite the statement. Its length L is 3 times its width into a mathematical equation as follows:

L = 3 W

We have to substitute L =3W in the equation 2 L + 2 W = 800

2(3 W) + 2 W = 800

8 W = 800

W =100 meters

Use the equation L = 3 W to find L.

L = 3 W = 225 meters

Use the formula of the area.

Area = L x W = 225 * 100 = 22500 meters 2.

So, the area of the rectangle=22500 meters 2.

Example online geometry solving problem 2:

A perimeter of the triangle is 50cm. If 2 of its sides are equal and also the third side is 5cm more than the equal sides, find the length of the third side?

Solution:

Let x = length of the equal side.

Third side=5 more than the equal side=x+5

So, the three sides are x, x and x+5.

P = sum of the three sides

x+ x+(x+5) =50

Combine like terms

3 x + 5=50

3x = 50 – 5

3x = 45

x =15cm (equal sides)

Length of the third side=x+5=15+5=20cm

The length of third side is 20cm.

Example online geometry solving problem 3:

A circle has an area of 100pi square units. What is the length of the circle's diameter and circumference?

Solution:

Area of the circle

A = (pi)*r^2

100pi = (pi)*r^2

(100pi) / pi = [(pi)*r^2] / pi

100= r^2

10 = r

So, the radius=10units

Diameter=2(radius) =20 units

Circumference= (pi)*d

=20pi units (or)

Substitute the value of pi=3.14

=62.8units

Circumference=20pi units (or) 62.8 units.

Understanding Quadratic Equation Calculator is always challenging for me but thanks to all math help websites to help me out.

Practice problems for online geometry solving:


Problems:

A circle has an area of 80pi square units. What is the length of the circle's diameter and circumference?
Answer: 16 pi units.

A circle has an area of 60pi square units. What is the length of the circle's diameter and circumference?
Answer: 12 pi units.