Introduction :-
In geometry, an arc is a segment of a differentiable curve in the two-dimensional plane; for example, a circular arc is a segment of the circumference of a circle. If the arc segment occupies a great circle (or great ellipse), it is considered a great-arc segment.I like to share this Math Pythagorean Theorem with you all through my article.
(Source : Wikipedia)
Example Problems for Solving Geometry Explanation
Problem 1:-
Solving geometry explanation to find the volume of cone with radius 7 cm and height 8 cm.
Solution:
Given: Radius = 7 cm
Height = 8 cm.
Volume of cone = (`1/3` ) * `pi` * radius2 * height
= (`1/3` ) * 3.14 * 72 * 8 ( multiplying these values)
= 0.33 * 3.14 * 49 *9 ( multiplying the values)
= 456.96 cubic cm.
The volume of cone is 456.96 cubic cm.
Problem 2:
Solving geometry explanation to find the Perimeter of Parallelogram for the side of a 8 and side of b is 6.
Solution:
Given: Side a = 8
Side b = 6
Perimeter of Parallelogram P = 2 * 8 + 2 * 6 ( multiplying the values)
P = 16 + 12
P = 28
The Perimeter of Parallelogram is 32
Problem 3:
Solving geometry explanation to find the circle area and circumference radius with 6 cm.
Solution:
Given: Radius = 6 cm
Area of Circle = `pi` * radius2 `pi` = 3.14
= 3.14 * 62
= 3.14 * 36 ( multiplying the values)
= 113.04 square cm.
The Area of Circle is 113.04 square cm
Circumference of Circle = 2 * `pi` * radius
= 2 * 3.14 * 6 ( multiplying the values)
= 37.68cm.
The Circumference of Circle 37.68 cm
More Example Problems for Solving Geometry Explanation
Problem 1:
Solving geometry explanation to find the Area of Triangle with height 3 cm and Base 7 cm.
Solution:
Given: Height = 3 cm
Base = 7 cm
Area of Triangle = (½) * height * base
= 0.5 * 3* 7 ( multiplying these values)
= 10.5 square cm.
The Area of Triangle 10.5 square cm
Problem 2:
Solving geometry explanation to find the Area of rhombus whose diagonal lengths are 5 cm and 8 cm.
Solution:
Area of Rhombus = (½) * Length of the diagonal 1 * Length of the diagonal 2
= `1/2` * 5* 8 ( multiplying these values)
= 20 square cm.
The Area of Triangle 20 square cm
In geometry, an arc is a segment of a differentiable curve in the two-dimensional plane; for example, a circular arc is a segment of the circumference of a circle. If the arc segment occupies a great circle (or great ellipse), it is considered a great-arc segment.I like to share this Math Pythagorean Theorem with you all through my article.
(Source : Wikipedia)
Example Problems for Solving Geometry Explanation
Problem 1:-
Solving geometry explanation to find the volume of cone with radius 7 cm and height 8 cm.
Solution:
Given: Radius = 7 cm
Height = 8 cm.
Volume of cone = (`1/3` ) * `pi` * radius2 * height
= (`1/3` ) * 3.14 * 72 * 8 ( multiplying these values)
= 0.33 * 3.14 * 49 *9 ( multiplying the values)
= 456.96 cubic cm.
The volume of cone is 456.96 cubic cm.
Problem 2:
Solving geometry explanation to find the Perimeter of Parallelogram for the side of a 8 and side of b is 6.
Solution:
Given: Side a = 8
Side b = 6
Perimeter of Parallelogram P = 2 * 8 + 2 * 6 ( multiplying the values)
P = 16 + 12
P = 28
The Perimeter of Parallelogram is 32
Problem 3:
Solving geometry explanation to find the circle area and circumference radius with 6 cm.
Solution:
Given: Radius = 6 cm
Area of Circle = `pi` * radius2 `pi` = 3.14
= 3.14 * 62
= 3.14 * 36 ( multiplying the values)
= 113.04 square cm.
The Area of Circle is 113.04 square cm
Circumference of Circle = 2 * `pi` * radius
= 2 * 3.14 * 6 ( multiplying the values)
= 37.68cm.
The Circumference of Circle 37.68 cm
More Example Problems for Solving Geometry Explanation
Problem 1:
Solving geometry explanation to find the Area of Triangle with height 3 cm and Base 7 cm.
Solution:
Given: Height = 3 cm
Base = 7 cm
Area of Triangle = (½) * height * base
= 0.5 * 3* 7 ( multiplying these values)
= 10.5 square cm.
The Area of Triangle 10.5 square cm
Problem 2:
Solving geometry explanation to find the Area of rhombus whose diagonal lengths are 5 cm and 8 cm.
Solution:
Area of Rhombus = (½) * Length of the diagonal 1 * Length of the diagonal 2
= `1/2` * 5* 8 ( multiplying these values)
= 20 square cm.
The Area of Triangle 20 square cm
