Introduction to surface area of a box:
Box is same as the cuboid. In box the dimensions are length, width and height. If all the dimensions are equal then the box is cube and if it is different then the box is cuboid. Box is a 3 dimensional image. A box has 8 vertices, 12 edges and 6 faces. Understanding Area of a Hexagon is always challenging for me but thanks to all math help websites to help me out.
Diagram and Formula – Surface Area of a Box:
Surface area of a box = 2(1w+lh+wh)
Where w`=>` width of the box
h`=>` height of the box
l`=>` length of the box. Is this topic how to construct parallel lines hard for you? Watch out for my coming posts.
Example Problems – Surface Area of a Box:
Example 1 :
Find the surface area of a box whose length, width and height are 12cm, 14cm, 16cm.
Solution:
Given that,
Length of the box = 12cm
Width of the box = 14cm
Height of the box=16cm.
Surface area of a box = 2(lw + lh + wh)
=2((12*14) +(12*16)+(14*16))
=2(168+192+224)
=2(584)
=1168cm3.
Example 2 :
Find the surface area of a box whose length, width and height are 2cm, 4cm, 6cm.
Solution:
Given that,
Length of the box = 2cm
Width of the box = 4cm
Height of the box=6cm.
Surface area of a box = 2(lw + lh + wh)
=2((2*4) +(2*6)+( 4*6))
=2(8+12+24)
=2(44)
=88cm3.
Example 3 :
Find the surface area of a box whose length, width and height are 8cm, 6cm, 4cm.
Solution:
Given that,
Length of the box = 8cm
Width of the box = 6cm
Height of the box=4cm.
Surface area of a box = 2(lw + lh + wh)
=2((8*6) +(8*4)+(6*4))
=2(48+32+24)
=2(104)
=208cm3.
Example 4 :
Find the surface area of a box whose length, width and height are 10cm, 20cm, 30cm.
Solution:
Given that,
Length of the box = 10cm
Width of the box = 20cm
Height of the box=30cm.
Surface area of a box = 2(lw + lh + wh)
=2((10*20) +(10*30)+(20*30))
=2(200+300+600)
=2(1100)
=2200cm3.
Box is same as the cuboid. In box the dimensions are length, width and height. If all the dimensions are equal then the box is cube and if it is different then the box is cuboid. Box is a 3 dimensional image. A box has 8 vertices, 12 edges and 6 faces. Understanding Area of a Hexagon is always challenging for me but thanks to all math help websites to help me out.
Diagram and Formula – Surface Area of a Box:
Where w`=>` width of the box
h`=>` height of the box
l`=>` length of the box. Is this topic how to construct parallel lines hard for you? Watch out for my coming posts.
Example Problems – Surface Area of a Box:
Example 1 :
Find the surface area of a box whose length, width and height are 12cm, 14cm, 16cm.
Solution:
Given that,
Length of the box = 12cm
Width of the box = 14cm
Height of the box=16cm.
Surface area of a box = 2(lw + lh + wh)
=2((12*14) +(12*16)+(14*16))
=2(168+192+224)
=2(584)
=1168cm3.
Example 2 :
Find the surface area of a box whose length, width and height are 2cm, 4cm, 6cm.
Solution:
Given that,
Length of the box = 2cm
Width of the box = 4cm
Height of the box=6cm.
Surface area of a box = 2(lw + lh + wh)
=2((2*4) +(2*6)+( 4*6))
=2(8+12+24)
=2(44)
=88cm3.
Example 3 :
Find the surface area of a box whose length, width and height are 8cm, 6cm, 4cm.
Solution:
Given that,
Length of the box = 8cm
Width of the box = 6cm
Height of the box=4cm.
Surface area of a box = 2(lw + lh + wh)
=2((8*6) +(8*4)+(6*4))
=2(48+32+24)
=2(104)
=208cm3.
Example 4 :
Find the surface area of a box whose length, width and height are 10cm, 20cm, 30cm.
Solution:
Given that,
Length of the box = 10cm
Width of the box = 20cm
Height of the box=30cm.
Surface area of a box = 2(lw + lh + wh)
=2((10*20) +(10*30)+(20*30))
=2(200+300+600)
=2(1100)
=2200cm3.
