Introduction to solve geometry placement test:
The division of math which deals with the measurement of lengths, angles, areas, perimeters and volumes of plane and solid figures is called geometry.we all knew placement is our dream in college life.In placement test, geometry plays an important role.Here solved geometry placement test papers with solutions given for your practice. Sample geometry placement test paper were given solve this test on your own without the help of a calculator, book, notes, or other people.
Solve geometry placement test:
Example 1:
A room inner space of diameter 150 cm has a wall around it. If the length of the outer edge of the wall is 60 cm, then find the width of the wall.
Solution:
Diameter of the room = 150 cm
Radius = 150 / 2 = 75 cm
Let width of wall = x cm then total radius = (75 + x) cm
Outer edge of the wall = 2 pi (75 + x) = 44/7 (75 + x) cm
But outer edge of wall = 660 cm
44/7 (75 x) = 660
75 + x = 660 7 / 44
= 105
X = 105 - 75
X = 30 cm
Example 2:
Find number of times will the wheel of a car rotate in a journey of 76 km if the diameter of the wheel is 36 cm?
Solution:
Diameter of the wheel = 36 cm
The Circumference of the wheel of diameter = D = 22 / 7 36 = 113 cm
Length of the journey = 76 km = 76*1000*100 cm
Number of times the wheel will rotate in covering the above journey
= `7600000 / 113`
= 67,256.63 .
Please express your views of this topic Volume of Triangular Prism by commenting on blog
Solve geometry placement test:Examples
Example 3.
Find the area of a rectangle of length = 9 cm,breadth = 6 cm.
Solution:
Length and breadth is given here,
we need to find the area ,
Area = l × b sq.units
=` 9 * 6` sq.cm
= 54 sq.cm
Example 4.
Find the perimeter of a rectangle of length = 6 cm,breadth = 5 cm.
Perimeter = 2 (l + b) units
Perimeter = 2 (6 + 5) units
= 22 cm.
Example 5:
A piece of thin wire which is circular, converted into a square of side 7cm. find the radius of circular wire.
Solution:
Side of a square = 7 cm
Its perimeter = `4* side` = `4 * 7` cm = 28 cm
Circumference of the circular wire = 28 cm. we know that c =`2*pi*r`
28 =` 2*(22/7)*r`
r = `(28*7)` /` (2* 22)`
= `196 / 44`
r = 4.454 cm
The division of math which deals with the measurement of lengths, angles, areas, perimeters and volumes of plane and solid figures is called geometry.we all knew placement is our dream in college life.In placement test, geometry plays an important role.Here solved geometry placement test papers with solutions given for your practice. Sample geometry placement test paper were given solve this test on your own without the help of a calculator, book, notes, or other people.
Solve geometry placement test:
Example 1:
A room inner space of diameter 150 cm has a wall around it. If the length of the outer edge of the wall is 60 cm, then find the width of the wall.
Solution:
Diameter of the room = 150 cm
Radius = 150 / 2 = 75 cm
Let width of wall = x cm then total radius = (75 + x) cm
Outer edge of the wall = 2 pi (75 + x) = 44/7 (75 + x) cm
But outer edge of wall = 660 cm
44/7 (75 x) = 660
75 + x = 660 7 / 44
= 105
X = 105 - 75
X = 30 cm
Example 2:
Find number of times will the wheel of a car rotate in a journey of 76 km if the diameter of the wheel is 36 cm?
Solution:
Diameter of the wheel = 36 cm
The Circumference of the wheel of diameter = D = 22 / 7 36 = 113 cm
Length of the journey = 76 km = 76*1000*100 cm
Number of times the wheel will rotate in covering the above journey
= `7600000 / 113`
= 67,256.63 .
Please express your views of this topic Volume of Triangular Prism by commenting on blog
Solve geometry placement test:Examples
Example 3.
Find the area of a rectangle of length = 9 cm,breadth = 6 cm.
Solution:
Length and breadth is given here,
we need to find the area ,
Area = l × b sq.units
=` 9 * 6` sq.cm
= 54 sq.cm
Example 4.
Find the perimeter of a rectangle of length = 6 cm,breadth = 5 cm.
Perimeter = 2 (l + b) units
Perimeter = 2 (6 + 5) units
= 22 cm.
Example 5:
A piece of thin wire which is circular, converted into a square of side 7cm. find the radius of circular wire.
Solution:
Side of a square = 7 cm
Its perimeter = `4* side` = `4 * 7` cm = 28 cm
Circumference of the circular wire = 28 cm. we know that c =`2*pi*r`
28 =` 2*(22/7)*r`
r = `(28*7)` /` (2* 22)`
= `196 / 44`
r = 4.454 cm
No comments:
Post a Comment